-------------- Original message ---------------------- From: "Don Sheldon" <don.sheldon@xxxxxxxxx> > Each step is 3/8ths of an inch taller and approximately 7/32nds wider > (actually 3/14ths, but good luck finding that on your ruler), so a six > pip would be 2 1/8" tall and 1 21/32" wide. Approximately. (Actually > 1 9/14") 3/14??? Let's try that again? Pips / Width / Height 1 / 18/32 / 32/32 2 / 25/32 / 44/32 3 / 32/32 / 56/32 Therefore... 4 / 39/32 / 68/32 5 / 46/32 / 80/32 6 / 53/32 / 92/32 which is indeed 1 21/32 wide, but I'd say 2 7/8 tall. In general... x / (7x+11)/32 / (12x+20)/32 From: Christopher Hickman <tophu@xxxxxxx> > > And I think that IS linear growth, pretty much by definition. > > Yeah. You're right. I realize now what I thought I meant: the angles are not > constant. As the pyramids get bigger, the get more squat (that is, the linear > growth of the base width is a larger ratio to the linear growth of the height). > So, if you were to take a hypothetical 10 pointer and cut of the top 1 inch of > the tip, it would NOT be a 1 pointer, because it would be waaaay too wide. Using the linear progression we've discovered, a -11/7 pip pyramid would have zero width and a height of 8/224 of an inch (0.03(571428)"). :-) Ryan