We now have our 3 best contenders fFor the Best Amateur Icehouse Game of 2009. (Or, it seems that way right this moment. The dust is still settling, but I think we have reached a consensus.) Crosswalk, Quicksand, and Stack Control. Last thing to be done is sort out some procedures. It's easy to over think this stuff, but some a decisions need to be made. I'm willing to go along with whatever. Here's some things to put on the record and commit to: Voting should be done as simply as possible: small slips of paper which list the 3 games, and say "pick your 1 fFavorite." Place your vote in a ballot box, to be counted Saturday afternoon. The winner is the one with the most votes. We will need printed copies of the rules to all 3. Easy enough. I previously mentioned I could print up some nice promotional poster things to have around the table, so people know what this is. Did we ever decide on an official name? I recall "Apex" being both loved and hated. I like "Apex Ice Award for Best Amateur Icehouse Game Design" Not actually that important, probably. But we should agree to something. Stack Control requires a chess board, Quicksand requires a set of Martian Coasters, and Crosswalk needs 1d6. I can supply some chessboards and probably dice, and maybe the Looneys could donate some coasters? There's generally some in the lab anyway, so maybe one or two sets could live at the voting table. I am in fFavor of having the rules available to play some of the other semi-finalists, as well. We have some really great submissions, and I think it might help people who are interested in the system to see that there's really a lot of great possibilities. Not to distract or dilute the voting, mind you (Although, maybe: An option to write in votes towards those not appearing on the ballot?) Useful, because I think this is really about all the awesome game designers. And lastly, we need a trophy prize of some sort. I thought of asking a glassblower I know to make something interesting. Cheers! --Scott -- A pizza with the radius 'z' and thickness 'a' has the volume pi*z*z*a.